13401433011 has 8 divisors (see below), whose sum is σ = 18069348240. Its totient is φ = 8833903232.

The previous prime is 13401433009. The next prime is 13401433027. The reversal of 13401433011 is 11033410431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13401433011 - 2¹ = 13401433009 is a prime.

It is a super-2 number, since 2×13401433011² (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13401433211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25096050 + ... + 25096583.

It is an arithmetic number, because the mean of its divisors is an integer number (2258668530).

Almost surely, 2^13401433011 is an apocalyptic number.

13401433011 is a deficient number, since it is larger than the sum of its proper divisors (4667915229).

13401433011 is an equidigital number, since it uses as much as digits as its factorization.

13401433011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50192725.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 13401433011 its reverse (11033410431), we get a palindrome (24434843442).

The spelling of 13401433011 in words is "thirteen billion, four hundred one million, four hundred thirty-three thousand, eleven".