1340214402401 has 4 divisors (see below), whose sum is σ = 1531673602752. Its totient is φ = 1148755202052.

The previous prime is 1340214402377. The next prime is 1340214402403. The reversal of 1340214402401 is 1042044120431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1340214402401 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1340214402403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95729600165 + ... + 95729600178.

It is an arithmetic number, because the mean of its divisors is an integer number (382918400688).

Almost surely, 2^{1340214402401} is an apocalyptic number.

It is an amenable number.

1340214402401 is a deficient number, since it is larger than the sum of its proper divisors (191459200351).

1340214402401 is an equidigital number, since it uses as much as digits as its factorization.

1340214402401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 191459200350.

The product of its (nonzero) digits is 3072, while the sum is 26.

Adding to 1340214402401 its reverse (1042044120431), we get a palindrome (2382258522832).

The spelling of 1340214402401 in words is "one trillion, three hundred forty billion, two hundred fourteen million, four hundred two thousand, four hundred one".