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1340221515043 is a prime number
BaseRepresentation
bin10011100000001011011…
…011010110010100100011
311202010100100020010020111
4103200023123112110203
5133424233201440133
62503404514152151
7165553636625545
oct23401333262443
94663310203214
101340221515043
11477426118814
121978b1582657
13994c8027b98
1448c1d339695
1524ce00b61cd
hex1380b6d6523

1340221515043 has 2 divisors, whose sum is σ = 1340221515044. Its totient is φ = 1340221515042.

The previous prime is 1340221515023. The next prime is 1340221515079. The reversal of 1340221515043 is 3405151220431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1340221515043 - 217 = 1340221383971 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1340221514996 and 1340221515014.

It is not a weakly prime, because it can be changed into another prime (1340221515023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670110757521 + 670110757522.

It is an arithmetic number, because the mean of its divisors is an integer number (670110757522).

Almost surely, 21340221515043 is an apocalyptic number.

1340221515043 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340221515043 is an equidigital number, since it uses as much as digits as its factorization.

1340221515043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 1340221515043 its reverse (3405151220431), we get a palindrome (4745372735474).

The spelling of 1340221515043 in words is "one trillion, three hundred forty billion, two hundred twenty-one million, five hundred fifteen thousand, forty-three".