13402222413201 has 6 divisors (see below), whose sum is σ = 19358765707970. Its totient is φ = 8934814942128.

The previous prime is 13402222413193. The next prime is 13402222413227. The reversal of 13402222413201 is 10231422220431.

13402222413201 is a `hidden beast` number, since 1 + 3 + 4 + 0 + 2 + 222 + 413 + 20 + 1 = 666.

It can be written as a sum of positive squares in only one way, i.e., 13401463961601 + 758451600 = 3660801^2 + 27540^2 .

It is not a de Polignac number, because 13402222413201 - 2³ = 13402222413193 is a prime.

It is a super-2 number, since 2×13402222413201² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13402222413271) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 744567911836 + ... + 744567911853.

Almost surely, 2^{13402222413201} is an apocalyptic number.

It is an amenable number.

13402222413201 is a deficient number, since it is larger than the sum of its proper divisors (5956543294769).

13402222413201 is a wasteful number, since it uses less digits than its factorization.

13402222413201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1489135823695 (or 1489135823692 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 27.

Adding to 13402222413201 its reverse (10231422220431), we get a palindrome (23633644633632).

The spelling of 13402222413201 in words is "thirteen trillion, four hundred two billion, two hundred twenty-two million, four hundred thirteen thousand, two hundred one".