13402223443041 has 4 divisors (see below), whose sum is σ = 17869631257392. Its totient is φ = 8934815628692.

The previous prime is 13402223443031. The next prime is 13402223443061. The reversal of 13402223443041 is 14034432220431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13402223443041 - 2¹³ = 13402223434849 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13402223442993 and 13402223443011.

It is not an unprimeable number, because it can be changed into a prime (13402223443031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2233703907171 + ... + 2233703907176.

It is an arithmetic number, because the mean of its divisors is an integer number (4467407814348).

Almost surely, 2^{13402223443041} is an apocalyptic number.

It is an amenable number.

13402223443041 is a deficient number, since it is larger than the sum of its proper divisors (4467407814351).

13402223443041 is an equidigital number, since it uses as much as digits as its factorization.

13402223443041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4467407814350.

The product of its (nonzero) digits is 55296, while the sum is 33.

Adding to 13402223443041 its reverse (14034432220431), we get a palindrome (27436655663472).

The spelling of 13402223443041 in words is "thirteen trillion, four hundred two billion, two hundred twenty-three million, four hundred forty-three thousand, forty-one".