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134023114003 = 715059373127
BaseRepresentation
bin111110011010001100…
…1100110110100010011
3110210221022010121112011
41330310121212310103
54143434404122003
6141322552243351
712453134446462
oct1746431466423
9423838117464
10134023114003
1151925610239
1221b840a0557
13c83b529b6c
1466b59189d9
15374615246d
hex1f34666d13

134023114003 has 8 divisors (see below), whose sum is σ = 135937992960. Its totient is φ = 132108991560.

The previous prime is 134023113937. The next prime is 134023114007. The reversal of 134023114003 is 300411320431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 134023114003 - 29 = 134023113491 is a prime.

It is a super-2 number, since 2×1340231140032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134023114007) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 172626 + ... + 545752.

It is an arithmetic number, because the mean of its divisors is an integer number (16992249120).

Almost surely, 2134023114003 is an apocalyptic number.

134023114003 is a deficient number, since it is larger than the sum of its proper divisors (1914878957).

134023114003 is an equidigital number, since it uses as much as digits as its factorization.

134023114003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 378257.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 134023114003 its reverse (300411320431), we get a palindrome (434434434434).

The spelling of 134023114003 in words is "one hundred thirty-four billion, twenty-three million, one hundred fourteen thousand, three".

Divisors: 1 71 5059 359189 373127 26492017 1887649493 134023114003