Base | Representation |
---|---|
bin | 1100001100000111100000… |
… | …1010111111110011001001 |
3 | 1202110020201022110222102121 |
4 | 3003001320022333303021 |
5 | 3224040414403042301 |
6 | 44300534344131241 |
7 | 2552166560211250 |
oct | 303017012776311 |
9 | 52406638428377 |
10 | 13402314112201 |
11 | 42a7986a11913 |
12 | 160555ba66b21 |
13 | 762aa9870101 |
14 | 34496568b797 |
15 | 1839592dd3a1 |
hex | c30782bfcc9 |
13402314112201 has 8 divisors (see below), whose sum is σ = 15317184685824. Its totient is φ = 11487507106560.
The previous prime is 13402314112199. The next prime is 13402314112211. The reversal of 13402314112201 is 10221141320431.
13402314112201 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13402314112201 - 21 = 13402314112199 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13402314112211) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15439345 + ... + 16284286.
It is an arithmetic number, because the mean of its divisors is an integer number (1914648085728).
Almost surely, 213402314112201 is an apocalyptic number.
It is an amenable number.
13402314112201 is a deficient number, since it is larger than the sum of its proper divisors (1914870573623).
13402314112201 is an equidigital number, since it uses as much as digits as its factorization.
13402314112201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31783991.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 13402314112201 its reverse (10221141320431), we get a palindrome (23623455432632).
The spelling of 13402314112201 in words is "thirteen trillion, four hundred two billion, three hundred fourteen million, one hundred twelve thousand, two hundred one".
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