Base | Representation |
---|---|
bin | 1100001100000111100011… |
… | …0010000000111010110001 |
3 | 1202110020202000201121212211 |
4 | 3003001320302000322301 |
5 | 3224040430012343101 |
6 | 44300535351252121 |
7 | 2552200043151133 |
oct | 303017062007261 |
9 | 52406660647784 |
10 | 13402324340401 |
11 | 42a7991768477 |
12 | 160556337a041 |
13 | 762aaba117b9 |
14 | 344966b91053 |
15 | 18395a15dc51 |
hex | c3078c80eb1 |
13402324340401 has 8 divisors (see below), whose sum is σ = 13764595325184. Its totient is φ = 13040055776880.
The previous prime is 13402324340399. The next prime is 13402324340417. The reversal of 13402324340401 is 10404342320431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13402324340401 - 21 = 13402324340399 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13402324340491) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19674816 + ... + 20344606.
It is an arithmetic number, because the mean of its divisors is an integer number (1720574415648).
Almost surely, 213402324340401 is an apocalyptic number.
It is an amenable number.
13402324340401 is a deficient number, since it is larger than the sum of its proper divisors (362270984783).
13402324340401 is an equidigital number, since it uses as much as digits as its factorization.
13402324340401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1210631.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 13402324340401 its reverse (10404342320431), we get a palindrome (23806666660832).
The spelling of 13402324340401 in words is "thirteen trillion, four hundred two billion, three hundred twenty-four million, three hundred forty thousand, four hundred one".
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