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13402324340401 = 37540803669791
BaseRepresentation
bin1100001100000111100011…
…0010000000111010110001
31202110020202000201121212211
43003001320302000322301
53224040430012343101
644300535351252121
72552200043151133
oct303017062007261
952406660647784
1013402324340401
1142a7991768477
12160556337a041
13762aaba117b9
14344966b91053
1518395a15dc51
hexc3078c80eb1

13402324340401 has 8 divisors (see below), whose sum is σ = 13764595325184. Its totient is φ = 13040055776880.

The previous prime is 13402324340399. The next prime is 13402324340417. The reversal of 13402324340401 is 10404342320431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13402324340401 - 21 = 13402324340399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13402324340491) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19674816 + ... + 20344606.

It is an arithmetic number, because the mean of its divisors is an integer number (1720574415648).

Almost surely, 213402324340401 is an apocalyptic number.

It is an amenable number.

13402324340401 is a deficient number, since it is larger than the sum of its proper divisors (362270984783).

13402324340401 is an equidigital number, since it uses as much as digits as its factorization.

13402324340401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1210631.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 13402324340401 its reverse (10404342320431), we get a palindrome (23806666660832).

The spelling of 13402324340401 in words is "thirteen trillion, four hundred two billion, three hundred twenty-four million, three hundred forty thousand, four hundred one".

Divisors: 1 37 540803 669791 20009711 24782267 362224982173 13402324340401