1340240115 has 16 divisors (see below), whose sum is σ = 2147191200. Its totient is φ = 713859072.

The previous prime is 1340240113. The next prime is 1340240117. The reversal of 1340240115 is 5110420431.

It is an interprime number because it is at equal distance from previous prime (1340240113) and next prime (1340240117).

It is not a de Polignac number, because 1340240115 - 2¹ = 1340240113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1340240091 and 1340240100.

It is not an unprimeable number, because it can be changed into a prime (1340240113) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 46560 + ... + 69629.

It is an arithmetic number, because the mean of its divisors is an integer number (134199450).

Almost surely, 2^1340240115 is an apocalyptic number.

1340240115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

1340240115 is a deficient number, since it is larger than the sum of its proper divisors (806951085).

1340240115 is a wasteful number, since it uses less digits than its factorization.

1340240115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 116966.

The product of its (nonzero) digits is 480, while the sum is 21.

The square root of 1340240115 is about 36609.2900095044. The cubic root of 1340240115 is about 1102.5396183849.

Adding to 1340240115 its reverse (5110420431), we get a palindrome (6450660546).

The spelling of 1340240115 in words is "one billion, three hundred forty million, two hundred forty thousand, one hundred fifteen".