13402924441 has 3 divisors (see below), whose sum is σ = 13403040213. Its totient is φ = 13402808670.

The previous prime is 13402924429. The next prime is 13402924471. The reversal of 13402924441 is 14442920431.

The square root of 13402924441 is 115771.

It is a perfect power (a square), and thus also a powerful number.

13402924441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a de Polignac number, because none of the positive numbers 2^k-13402924441 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13402924397 and 13402924406.

It is not an unprimeable number, because it can be changed into a prime (13402924471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 2 ways as a sum of consecutive naturals, for example, 57886 + ... + 173656.

It is an arithmetic number, because the mean of its divisors is an integer number (4467680071).

Almost surely, 2^13402924441 is an apocalyptic number.

13402924441 is the 115771-st square number.

13402924441 is the 57886-th centered octagonal number.

It is an amenable number.

13402924441 is a deficient number, since it is larger than the sum of its proper divisors (115772).

13402924441 is an frugal number, since it uses more digits than its factorization.

13402924441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 231542 (or 115771 counting only the distinct ones).

The product of its (nonzero) digits is 27648, while the sum is 34.

The spelling of 13402924441 in words is "thirteen billion, four hundred two million, nine hundred twenty-four thousand, four hundred forty-one".