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134029370753 is a prime number
BaseRepresentation
bin111110011010011000…
…1011110010110000001
3110210221201220111011122
41330310301132112001
54143443004331003
6141323334322025
712453241565645
oct1746461362601
9423851814148
10134029370753
11519290a4003
1221b861b9315
13c83c90a995
1466b66a6c25
15374698b238
hex1f34c5e581

134029370753 has 2 divisors, whose sum is σ = 134029370754. Its totient is φ = 134029370752.

The previous prime is 134029370737. The next prime is 134029370767. The reversal of 134029370753 is 357073920431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 92520605584 + 41508765169 = 304172^2 + 203737^2 .

It is an emirp because it is prime and its reverse (357073920431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134029370753 - 24 = 134029370737 is a prime.

It is a super-3 number, since 3×1340293707533 (a number of 34 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (134029370953) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67014685376 + 67014685377.

It is an arithmetic number, because the mean of its divisors is an integer number (67014685377).

Almost surely, 2134029370753 is an apocalyptic number.

It is an amenable number.

134029370753 is a deficient number, since it is larger than the sum of its proper divisors (1).

134029370753 is an equidigital number, since it uses as much as digits as its factorization.

134029370753 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 476280, while the sum is 44.

The spelling of 134029370753 in words is "one hundred thirty-four billion, twenty-nine million, three hundred seventy thousand, seven hundred fifty-three".