134029433 has 2 divisors, whose sum is σ = 134029434. Its totient is φ = 134029432.

The previous prime is 134029391. The next prime is 134029463. The reversal of 134029433 is 334920431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 78198649 + 55830784 = 8843^2 + 7472^2 .

It is a cyclic number.

It is not a de Polignac number, because 134029433 - 2⁸ = 134029177 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 134029396 and 134029405.

It is not a weakly prime, because it can be changed into another prime (134029463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67014716 + 67014717.

It is an arithmetic number, because the mean of its divisors is an integer number (67014717).

Almost surely, 2^134029433 is an apocalyptic number.

It is an amenable number.

134029433 is a deficient number, since it is larger than the sum of its proper divisors (1).

134029433 is an equidigital number, since it uses as much as digits as its factorization.

134029433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7776, while the sum is 29.

The square root of 134029433 is about 11577.1081449557. The cubic root of 134029433 is about 511.7604584730.

Adding to 134029433 its reverse (334920431), we get a palindrome (468949864).

The spelling of 134029433 in words is "one hundred thirty-four million, twenty-nine thousand, four hundred thirty-three".