Base | Representation |
---|---|
bin | 11110011110011001001010… |
… | …110001110111001110001001 |
3 | 122120120010212102120100020120 |
4 | 132132121022301313032021 |
5 | 120031421422012233301 |
6 | 1153020311150213453 |
7 | 40142230305544035 |
oct | 3636311261671611 |
9 | 576503772510216 |
10 | 134030004024201 |
11 | 3978489513130a |
12 | 13047ab51b4289 |
13 | 59a2c8a52459c |
14 | 25151302b31c5 |
15 | 10766646c4e36 |
hex | 79e64ac77389 |
134030004024201 has 8 divisors (see below), whose sum is σ = 178795891547040. Its totient is φ = 89308726258752.
The previous prime is 134030004024181. The next prime is 134030004024227. The reversal of 134030004024201 is 102420400030431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 134030004024201 - 213 = 134030004016009 is a prime.
It is not an unprimeable number, because it can be changed into a prime (134030004224201) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11152432336 + ... + 11152444353.
It is an arithmetic number, because the mean of its divisors is an integer number (22349486443380).
Almost surely, 2134030004024201 is an apocalyptic number.
It is an amenable number.
134030004024201 is a deficient number, since it is larger than the sum of its proper divisors (44765887522839).
134030004024201 is a wasteful number, since it uses less digits than its factorization.
134030004024201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22304878695.
The product of its (nonzero) digits is 2304, while the sum is 24.
Adding to 134030004024201 its reverse (102420400030431), we get a palindrome (236450404054632).
The spelling of 134030004024201 in words is "one hundred thirty-four trillion, thirty billion, four million, twenty-four thousand, two hundred one".
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