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134030565017 = 311430966447
BaseRepresentation
bin111110011010011011…
…0000001111010011001
3110210221211011011101122
41330310312001322121
54143443311040032
6141323420055025
712453255001526
oct1746466017231
9423854134348
10134030565017
115192983a2a8
1221b86694475
13c83cc3844b
1466b68d814d
153746b25012
hex1f34d81e99

134030565017 has 4 divisors (see below), whose sum is σ = 134461531776. Its totient is φ = 133599598260.

The previous prime is 134030565013. The next prime is 134030565023. The reversal of 134030565017 is 710565030431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 134030565017 - 22 = 134030565013 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134030565013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 215482913 + ... + 215483534.

It is an arithmetic number, because the mean of its divisors is an integer number (33615382944).

Almost surely, 2134030565017 is an apocalyptic number.

It is an amenable number.

134030565017 is a deficient number, since it is larger than the sum of its proper divisors (430966759).

134030565017 is an equidigital number, since it uses as much as digits as its factorization.

134030565017 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 430966758.

The product of its (nonzero) digits is 37800, while the sum is 35.

Adding to 134030565017 its reverse (710565030431), we get a palindrome (844595595448).

The spelling of 134030565017 in words is "one hundred thirty-four billion, thirty million, five hundred sixty-five thousand, seventeen".

Divisors: 1 311 430966447 134030565017