Base | Representation |
---|---|
bin | 1100001100001010011101… |
… | …0000101110100000110010 |
3 | 1202110022202101001201111202 |
4 | 3003002213100232200302 |
5 | 3224044024130042120 |
6 | 44301145005211202 |
7 | 2552225262315242 |
oct | 303024720564062 |
9 | 52408671051452 |
10 | 13403104143410 |
11 | 42a8251963a73 |
12 | 1605740560b02 |
13 | 762ba44426b7 |
14 | 3449dc57db22 |
15 | 1839a3846875 |
hex | c30a742e832 |
13403104143410 has 32 divisors (see below), whose sum is σ = 24777901181952. Its totient is φ = 5216286219840.
The previous prime is 13403104143391. The next prime is 13403104143421. The reversal of 13403104143410 is 1434140130431.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 52969895 + ... + 53222325.
It is an arithmetic number, because the mean of its divisors is an integer number (774309411936).
Almost surely, 213403104143410 is an apocalyptic number.
13403104143410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13403104143410 is a deficient number, since it is larger than the sum of its proper divisors (11374797038542).
13403104143410 is a wasteful number, since it uses less digits than its factorization.
13403104143410 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 395978.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 13403104143410 its reverse (1434140130431), we get a palindrome (14837244273841).
The spelling of 13403104143410 in words is "thirteen trillion, four hundred three billion, one hundred four million, one hundred forty-three thousand, four hundred ten".
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