Base | Representation |
---|---|
bin | 111110011010011100… |
… | …1100101000100011001 |
3 | 110210221212220102201002 |
4 | 1330310321211010121 |
5 | 4143444030323244 |
6 | 141323452034345 |
7 | 12453265625255 |
oct | 1746471450431 |
9 | 423855812632 |
10 | 134031495449 |
11 | 5192a315355 |
12 | 21b86a629b5 |
13 | c8401a2ab7 |
14 | 66b6a9b265 |
15 | 3746c5aa4e |
hex | 1f34e65119 |
134031495449 has 2 divisors, whose sum is σ = 134031495450. Its totient is φ = 134031495448.
The previous prime is 134031495401. The next prime is 134031495467. The reversal of 134031495449 is 944594130431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 72846010000 + 61185485449 = 269900^2 + 247357^2 .
It is a cyclic number.
It is not a de Polignac number, because 134031495449 - 212 = 134031491353 is a prime.
It is not a weakly prime, because it can be changed into another prime (134031495349) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67015747724 + 67015747725.
It is an arithmetic number, because the mean of its divisors is an integer number (67015747725).
Almost surely, 2134031495449 is an apocalyptic number.
It is an amenable number.
134031495449 is a deficient number, since it is larger than the sum of its proper divisors (1).
134031495449 is an equidigital number, since it uses as much as digits as its factorization.
134031495449 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 933120, while the sum is 47.
The spelling of 134031495449 in words is "one hundred thirty-four billion, thirty-one million, four hundred ninety-five thousand, four hundred forty-nine".
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