13403204422344 has 192 divisors, whose sum is σ = 39892559616000. Its totient is φ = 4031620364160.

The previous prime is 13403204422337. The next prime is 13403204422379. The reversal of 13403204422344 is 44322440230431.

13403204422344 is a `hidden beast` number, since 1 + 3 + 403 + 20 + 4 + 4 + 223 + 4 + 4 = 666.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a junction number, because it is equal to n+sod(n) for n = 13403204422299 and 13403204422308.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1069939009 + ... + 1069951535.

It is an arithmetic number, because the mean of its divisors is an integer number (207773748000).

Almost surely, 2^{13403204422344} is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13403204422344, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19946279808000).

13403204422344 is an abundant number, since it is smaller than the sum of its proper divisors (26489355193656).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13403204422344 is a wasteful number, since it uses less digits than its factorization.

13403204422344 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22408 (or 22401 counting only the distinct ones).

The product of its (nonzero) digits is 221184, while the sum is 36.

Adding to 13403204422344 its reverse (44322440230431), we get a palindrome (57725644652775).

The spelling of 13403204422344 in words is "thirteen trillion, four hundred three billion, two hundred four million, four hundred twenty-two thousand, three hundred forty-four".