Base | Representation |
---|---|
bin | 11000111101110011… |
… | …00111011010111011 |
3 | 1021121002201022021221 |
4 | 30132321213122323 |
5 | 204422222301133 |
6 | 10053555412511 |
7 | 653101233436 |
oct | 143671473273 |
9 | 37532638257 |
10 | 13403322043 |
11 | 575890a261 |
12 | 27208b4137 |
13 | 1357b073b7 |
14 | 91215681d |
15 | 536a6ea2d |
hex | 31ee676bb |
13403322043 has 4 divisors (see below), whose sum is σ = 13477373728. Its totient is φ = 13329270360.
The previous prime is 13403322017. The next prime is 13403322047. The reversal of 13403322043 is 34022330431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13403322043 - 25 = 13403322011 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13403321999 and 13403322017.
It is not an unprimeable number, because it can be changed into a prime (13403322047) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37025571 + ... + 37025932.
It is an arithmetic number, because the mean of its divisors is an integer number (3369343432).
Almost surely, 213403322043 is an apocalyptic number.
13403322043 is a deficient number, since it is larger than the sum of its proper divisors (74051685).
13403322043 is an equidigital number, since it uses as much as digits as its factorization.
13403322043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 74051684.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 13403322043 its reverse (34022330431), we get a palindrome (47425652474).
The spelling of 13403322043 in words is "thirteen billion, four hundred three million, three hundred twenty-two thousand, forty-three".
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