134034103430011 has 4 divisors (see below), whose sum is σ = 134034569617000. Its totient is φ = 134033637243024.

The previous prime is 134034103429997. The next prime is 134034103430033. The reversal of 134034103430011 is 110034301430431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-134034103430011 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134034103430911) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 232661961 + ... + 233237338.

It is an arithmetic number, because the mean of its divisors is an integer number (33508642404250).

Almost surely, 2^{134034103430011} is an apocalyptic number.

134034103430011 is a deficient number, since it is larger than the sum of its proper divisors (466186989).

134034103430011 is an equidigital number, since it uses as much as digits as its factorization.

134034103430011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 466186988.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 134034103430011 its reverse (110034301430431), we get a palindrome (244068404860442).

The spelling of 134034103430011 in words is "one hundred thirty-four trillion, thirty-four billion, one hundred three million, four hundred thirty thousand, eleven".