Base | Representation |
---|---|
bin | 111110011010100010… |
… | …0101111011010111001 |
3 | 110210222002102002101212 |
4 | 1330311010233122321 |
5 | 4144000302441213 |
6 | 141324034452505 |
7 | 12453332532653 |
oct | 1746504573271 |
9 | 423862362355 |
10 | 134034421433 |
11 | 51930a33720 |
12 | 21b87a34135 |
13 | c840988853 |
14 | 66b721d6d3 |
15 | 37471379a8 |
hex | 1f3512f6b9 |
134034421433 has 16 divisors (see below), whose sum is σ = 146923929600. Its totient is φ = 121263745680.
The previous prime is 134034421421. The next prime is 134034421441. The reversal of 134034421433 is 334124430431.
It is not a de Polignac number, because 134034421433 - 222 = 134030227129 is a prime.
It is a super-2 number, since 2×1340344214332 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 134034421433.
It is not an unprimeable number, because it can be changed into a prime (134034421483) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1895528 + ... + 1964966.
It is an arithmetic number, because the mean of its divisors is an integer number (9182745600).
Almost surely, 2134034421433 is an apocalyptic number.
It is an amenable number.
134034421433 is a deficient number, since it is larger than the sum of its proper divisors (12889508167).
134034421433 is a wasteful number, since it uses less digits than its factorization.
134034421433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70292.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 134034421433 its reverse (334124430431), we get a palindrome (468158851864).
The spelling of 134034421433 in words is "one hundred thirty-four billion, thirty-four million, four hundred twenty-one thousand, four hundred thirty-three".
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