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134035434024497 is a prime number
BaseRepresentation
bin11110011110011110001110…
…011011101010111000110001
3122120120122212212001221022122
4132132132032123222320301
5120032014032102240442
61153023010042044025
740142512002022505
oct3636361633527061
9576518785057278
10134035434024497
1139787121234965
1213048b6b7a9615
1359a3644499905
1425154c7508305
151076881268dd2
hex79e78e6eae31

134035434024497 has 2 divisors, whose sum is σ = 134035434024498. Its totient is φ = 134035434024496.

The previous prime is 134035434024467. The next prime is 134035434024517. The reversal of 134035434024497 is 794420434530431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 106498086283681 + 27537347740816 = 10319791^2 + 5247604^2 .

It is a cyclic number.

It is not a de Polignac number, because 134035434024497 - 226 = 134035366915633 is a prime.

It is a super-2 number, since 2×1340354340244972 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (134035434024467) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67017717012248 + 67017717012249.

It is an arithmetic number, because the mean of its divisors is an integer number (67017717012249).

Almost surely, 2134035434024497 is an apocalyptic number.

It is an amenable number.

134035434024497 is a deficient number, since it is larger than the sum of its proper divisors (1).

134035434024497 is an equidigital number, since it uses as much as digits as its factorization.

134035434024497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17418240, while the sum is 53.

The spelling of 134035434024497 in words is "one hundred thirty-four trillion, thirty-five billion, four hundred thirty-four million, twenty-four thousand, four hundred ninety-seven".