Base | Representation |
---|---|
bin | 10011100000010011111… |
… | …100001101010000110001 |
3 | 11202010201021222201001101 |
4 | 103200103330031100301 |
5 | 133430031233041132 |
6 | 2503431015404401 |
7 | 165560322650545 |
oct | 23402374152061 |
9 | 4663637881041 |
10 | 1340364346417 |
11 | 477499804078 |
12 | 197931383701 |
13 | 9951b7b6ba5 |
14 | 48c342b9a25 |
15 | 24cec8cb7e7 |
hex | 13813f0d431 |
1340364346417 has 2 divisors, whose sum is σ = 1340364346418. Its totient is φ = 1340364346416.
The previous prime is 1340364346397. The next prime is 1340364346421. The reversal of 1340364346417 is 7146434630431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1096761885696 + 243602460721 = 1047264^2 + 493561^2 .
It is a cyclic number.
It is not a de Polignac number, because 1340364346417 - 219 = 1340363822129 is a prime.
It is a super-2 number, since 2×13403643464172 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1340364346117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670182173208 + 670182173209.
It is an arithmetic number, because the mean of its divisors is an integer number (670182173209).
Almost surely, 21340364346417 is an apocalyptic number.
It is an amenable number.
1340364346417 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340364346417 is an equidigital number, since it uses as much as digits as its factorization.
1340364346417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1741824, while the sum is 46.
Adding to 1340364346417 its reverse (7146434630431), we get a palindrome (8486798976848).
The spelling of 1340364346417 in words is "one trillion, three hundred forty billion, three hundred sixty-four million, three hundred forty-six thousand, four hundred seventeen".
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