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134043351577 = 283473651419
BaseRepresentation
bin111110011010110011…
…0110011101000011001
3110210222201012210020221
41330311212303220121
54144010044222302
6141324554120041
712453501455242
oct1746546635031
9423881183227
10134043351577
1151935a83003
1221b8aa20021
13c842794465
1466b84a5cc9
153747ced937
hex1f359b3a19

134043351577 has 4 divisors (see below), whose sum is σ = 134517003280. Its totient is φ = 133569699876.

The previous prime is 134043351523. The next prime is 134043351581. The reversal of 134043351577 is 775153340431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134043351577 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134043351587) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 236825427 + ... + 236825992.

It is an arithmetic number, because the mean of its divisors is an integer number (33629250820).

Almost surely, 2134043351577 is an apocalyptic number.

It is an amenable number.

134043351577 is a deficient number, since it is larger than the sum of its proper divisors (473651703).

134043351577 is an equidigital number, since it uses as much as digits as its factorization.

134043351577 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 473651702.

The product of its (nonzero) digits is 529200, while the sum is 43.

The spelling of 134043351577 in words is "one hundred thirty-four billion, forty-three million, three hundred fifty-one thousand, five hundred seventy-seven".

Divisors: 1 283 473651419 134043351577