1340434131 has 4 divisors (see below), whose sum is σ = 1787245512. Its totient is φ = 893622752.

The previous prime is 1340434111. The next prime is 1340434163. The reversal of 1340434131 is 1314340431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1340434131 - 2⁵ = 1340434099 is a prime.

It is a super-2 number, since 2×1340434131² = 3593527319099450322, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1340434111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223405686 + ... + 223405691.

It is an arithmetic number, because the mean of its divisors is an integer number (446811378).

Almost surely, 2^1340434131 is an apocalyptic number.

1340434131 is a deficient number, since it is larger than the sum of its proper divisors (446811381).

1340434131 is an equidigital number, since it uses as much as digits as its factorization.

1340434131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 446811380.

The product of its (nonzero) digits is 1728, while the sum is 24.

The square root of 1340434131 is about 36611.9397328249. The cubic root of 1340434131 is about 1102.5928178087.

Adding to 1340434131 its reverse (1314340431), we get a palindrome (2654774562).

The spelling of 1340434131 in words is "one billion, three hundred forty million, four hundred thirty-four thousand, one hundred thirty-one".