1340434333001 has 4 divisors (see below), whose sum is σ = 1340658454404. Its totient is φ = 1340210211600.

The previous prime is 1340434332949. The next prime is 1340434333031. The reversal of 1340434333001 is 1003334340431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 383314527376 + 957119805625 = 619124^2 + 978325^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1340434333001 is a prime.

It is a super-3 number, since 3×1340434333001³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1340434333031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 112051730 + ... + 112063691.

It is an arithmetic number, because the mean of its divisors is an integer number (335164613601).

Almost surely, 2^{1340434333001} is an apocalyptic number.

It is an amenable number.

1340434333001 is a deficient number, since it is larger than the sum of its proper divisors (224121403).

1340434333001 is an equidigital number, since it uses as much as digits as its factorization.

1340434333001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 224121402.

The product of its (nonzero) digits is 15552, while the sum is 29.

Adding to 1340434333001 its reverse (1003334340431), we get a palindrome (2343768673432).

The spelling of 1340434333001 in words is "one trillion, three hundred forty billion, four hundred thirty-four million, three hundred thirty-three thousand, one".