13404350041 has 2 divisors, whose sum is σ = 13404350042. Its totient is φ = 13404350040.

The previous prime is 13404349979. The next prime is 13404350081. The reversal of 13404350041 is 14005340431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13272192025 + 132158016 = 115205^2 + 11496^2 .

It is a cyclic number.

It is not a de Polignac number, because 13404350041 - 2¹⁷ = 13404218969 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13404349988 and 13404350015.

It is not a weakly prime, because it can be changed into another prime (13404350081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702175020 + 6702175021.

It is an arithmetic number, because the mean of its divisors is an integer number (6702175021).

Almost surely, 2^13404350041 is an apocalyptic number.

It is an amenable number.

13404350041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13404350041 is an equidigital number, since it uses as much as digits as its factorization.

13404350041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 13404350041 its reverse (14005340431), we get a palindrome (27409690472).

The spelling of 13404350041 in words is "thirteen billion, four hundred four million, three hundred fifty thousand, forty-one".