Base | Representation |
---|---|
bin | 10011100000011010011… |
… | …111110100010101000011 |
3 | 11202010222221222012102111 |
4 | 103200122133310111003 |
5 | 133430242413013041 |
6 | 2503445545200151 |
7 | 165563126634502 |
oct | 23403237642503 |
9 | 4663887865374 |
10 | 1340474344771 |
11 | 477545904501 |
12 | 197962190057 |
13 | 9953851b583 |
14 | 48c44b50839 |
15 | 24d073a8981 |
hex | 1381a7f4543 |
1340474344771 has 4 divisors (see below), whose sum is σ = 1340479882944. Its totient is φ = 1340468806600.
The previous prime is 1340474344717. The next prime is 1340474344787. The reversal of 1340474344771 is 1774434740431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1340474344771 - 223 = 1340465956163 is a prime.
It is a Smith number, since the sum of its digits (49) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1340474344471) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2388595 + ... + 2895916.
It is an arithmetic number, because the mean of its divisors is an integer number (335119970736).
Almost surely, 21340474344771 is an apocalyptic number.
1340474344771 is a deficient number, since it is larger than the sum of its proper divisors (5538173).
1340474344771 is an equidigital number, since it uses as much as digits as its factorization.
1340474344771 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5538172.
The product of its (nonzero) digits is 3161088, while the sum is 49.
The spelling of 1340474344771 in words is "one trillion, three hundred forty billion, four hundred seventy-four million, three hundred forty-four thousand, seven hundred seventy-one".
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