1340474814051 has 4 divisors (see below), whose sum is σ = 1787299752072. Its totient is φ = 893649876032.

The previous prime is 1340474814047. The next prime is 1340474814053. The reversal of 1340474814051 is 1504184740431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1340474814051 - 2² = 1340474814047 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1340474813994 and 1340474814012.

It is not an unprimeable number, because it can be changed into a prime (1340474814053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223412469006 + ... + 223412469011.

It is an arithmetic number, because the mean of its divisors is an integer number (446824938018).

Almost surely, 2^{1340474814051} is an apocalyptic number.

1340474814051 is a deficient number, since it is larger than the sum of its proper divisors (446824938021).

1340474814051 is an equidigital number, since it uses as much as digits as its factorization.

1340474814051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 446824938020.

The product of its (nonzero) digits is 215040, while the sum is 42.

The spelling of 1340474814051 in words is "one trillion, three hundred forty billion, four hundred seventy-four million, eight hundred fourteen thousand, fifty-one".