Base | Representation |
---|---|
bin | 10011100000011010111… |
… | …010111111111111000001 |
3 | 11202011000110101012221201 |
4 | 103200122322333333001 |
5 | 133430301224023101 |
6 | 2503450402021201 |
7 | 165563244333103 |
oct | 23403272777701 |
9 | 4664013335851 |
10 | 1340481470401 |
11 | 477549931057 |
12 | 197964647801 |
13 | 99539b44a18 |
14 | 48c45a87573 |
15 | 24d07d14e01 |
hex | 1381aebffc1 |
1340481470401 has 2 divisors, whose sum is σ = 1340481470402. Its totient is φ = 1340481470400.
The previous prime is 1340481470353. The next prime is 1340481470431. The reversal of 1340481470401 is 1040741840431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 906305904001 + 434175566400 = 952001^2 + 658920^2 .
It is an emirp because it is prime and its reverse (1040741840431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1340481470401 - 213 = 1340481462209 is a prime.
It is not a weakly prime, because it can be changed into another prime (1340481470431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670240735200 + 670240735201.
It is an arithmetic number, because the mean of its divisors is an integer number (670240735201).
Almost surely, 21340481470401 is an apocalyptic number.
It is an amenable number.
1340481470401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340481470401 is an equidigital number, since it uses as much as digits as its factorization.
1340481470401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43008, while the sum is 37.
The spelling of 1340481470401 in words is "one trillion, three hundred forty billion, four hundred eighty-one million, four hundred seventy thousand, four hundred one".
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