Base | Representation |
---|---|
bin | 11000111110000001… |
… | …00011110000011001 |
3 | 1021121020010202212021 |
4 | 30133000203300121 |
5 | 204423204021131 |
6 | 10054102414441 |
7 | 653122553524 |
oct | 143700436031 |
9 | 37536122767 |
10 | 13405142041 |
11 | 5759942695 |
12 | 2721431421 |
13 | 13582c3915 |
14 | 9124abbbb |
15 | 536ccde11 |
hex | 31f023c19 |
13405142041 has 2 divisors, whose sum is σ = 13405142042. Its totient is φ = 13405142040.
The previous prime is 13405142021. The next prime is 13405142053. The reversal of 13405142041 is 14024150431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12588840000 + 816302041 = 112200^2 + 28571^2 .
It is an emirp because it is prime and its reverse (14024150431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13405142041 - 213 = 13405133849 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13405141997 and 13405142015.
It is not a weakly prime, because it can be changed into another prime (13405142011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702571020 + 6702571021.
It is an arithmetic number, because the mean of its divisors is an integer number (6702571021).
Almost surely, 213405142041 is an apocalyptic number.
It is an amenable number.
13405142041 is a deficient number, since it is larger than the sum of its proper divisors (1).
13405142041 is an equidigital number, since it uses as much as digits as its factorization.
13405142041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1920, while the sum is 25.
Adding to 13405142041 its reverse (14024150431), we get a palindrome (27429292472).
The spelling of 13405142041 in words is "thirteen billion, four hundred five million, one hundred forty-two thousand, forty-one".
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