Base | Representation |
---|---|
bin | 10011100000011110000… |
… | …001010010100111110011 |
3 | 11202011011002012010021101 |
4 | 103200132001102213303 |
5 | 133430403030420001 |
6 | 2503455500105231 |
7 | 165564445220551 |
oct | 23403601224763 |
9 | 4664132163241 |
10 | 1340533451251 |
11 | 477576205035 |
12 | 197979b35217 |
13 | 99547844917 |
14 | 48c4c938bd1 |
15 | 24d0c681a01 |
hex | 1381e0529f3 |
1340533451251 has 2 divisors, whose sum is σ = 1340533451252. Its totient is φ = 1340533451250.
The previous prime is 1340533451221. The next prime is 1340533451291. The reversal of 1340533451251 is 1521543350431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1340533451251 - 25 = 1340533451219 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1340533451251.
It is not a weakly prime, because it can be changed into another prime (1340533451221) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670266725625 + 670266725626.
It is an arithmetic number, because the mean of its divisors is an integer number (670266725626).
Almost surely, 21340533451251 is an apocalyptic number.
1340533451251 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340533451251 is an equidigital number, since it uses as much as digits as its factorization.
1340533451251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108000, while the sum is 37.
The spelling of 1340533451251 in words is "one trillion, three hundred forty billion, five hundred thirty-three million, four hundred fifty-one thousand, two hundred fifty-one".
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