Base | Representation |
---|---|
bin | 1100001100010011001100… |
… | …1010001010101001110011 |
3 | 1202110112210221112021101102 |
4 | 3003010303022022221303 |
5 | 3224113331003441112 |
6 | 44302213531355015 |
7 | 2552340402255545 |
oct | 303046312125163 |
9 | 52415727467342 |
10 | 13405451233907 |
11 | 42a9246818887 |
12 | 16060965b2a6b |
13 | 763189794845 |
14 | 344b82189695 |
15 | 183a8e91abc2 |
hex | c313328aa73 |
13405451233907 has 2 divisors, whose sum is σ = 13405451233908. Its totient is φ = 13405451233906.
The previous prime is 13405451233877. The next prime is 13405451233973. The reversal of 13405451233907 is 70933215450431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13405451233907 - 26 = 13405451233843 is a prime.
It is a super-2 number, since 2×134054512339072 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13405451233807) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702725616953 + 6702725616954.
It is an arithmetic number, because the mean of its divisors is an integer number (6702725616954).
Almost surely, 213405451233907 is an apocalyptic number.
13405451233907 is a deficient number, since it is larger than the sum of its proper divisors (1).
13405451233907 is an equidigital number, since it uses as much as digits as its factorization.
13405451233907 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1360800, while the sum is 47.
The spelling of 13405451233907 in words is "thirteen trillion, four hundred five billion, four hundred fifty-one million, two hundred thirty-three thousand, nine hundred seven".
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