Search a number
-
+
13405535242147 is a prime number
BaseRepresentation
bin1100001100010011100000…
…1010101000011110100011
31202110120000210121100000201
43003010320022220132203
53224114014010222042
644302230132130031
72552342442314536
oct303047012503643
952416023540021
1013405535242147
1142a928a187484
1216060ba766917
137631a0cc9469
14344b8d3b6a1d
15183a96eb21b7
hexc31382a87a3

13405535242147 has 2 divisors, whose sum is σ = 13405535242148. Its totient is φ = 13405535242146.

The previous prime is 13405535242139. The next prime is 13405535242163. The reversal of 13405535242147 is 74124253550431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13405535242147 - 23 = 13405535242139 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13405535242097 and 13405535242106.

It is not a weakly prime, because it can be changed into another prime (13405535245147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702767621073 + 6702767621074.

It is an arithmetic number, because the mean of its divisors is an integer number (6702767621074).

Almost surely, 213405535242147 is an apocalyptic number.

13405535242147 is a deficient number, since it is larger than the sum of its proper divisors (1).

13405535242147 is an equidigital number, since it uses as much as digits as its factorization.

13405535242147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016000, while the sum is 46.

Adding to 13405535242147 its reverse (74124253550431), we get a palindrome (87529788792578).

The spelling of 13405535242147 in words is "thirteen trillion, four hundred five billion, five hundred thirty-five million, two hundred forty-two thousand, one hundred forty-seven".