Base | Representation |
---|---|
bin | 111110011011001010… |
… | …0110100010100101010 |
3 | 110211000112220120110120 |
4 | 1330312110310110222 |
5 | 4144021141204114 |
6 | 141330104424110 |
7 | 12454006131654 |
oct | 1746624642452 |
9 | 424015816416 |
10 | 134055413034 |
11 | 51941870a54 |
12 | 21b92a78036 |
13 | c84512840a |
14 | 66b9d256d4 |
15 | 3748dd25a9 |
hex | 1f3653452a |
134055413034 has 8 divisors (see below), whose sum is σ = 268110826080. Its totient is φ = 44685137676.
The previous prime is 134055413003. The next prime is 134055413047. The reversal of 134055413034 is 430314550431.
It is a sphenic number, since it is the product of 3 distinct primes.
134055413034 is an admirable number.
It is a junction number, because it is equal to n+sod(n) for n = 134055412986 and 134055413004.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11171284414 + ... + 11171284425.
It is an arithmetic number, because the mean of its divisors is an integer number (33513853260).
Almost surely, 2134055413034 is an apocalyptic number.
134055413034 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134055413034 is a wasteful number, since it uses less digits than its factorization.
134055413034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22342568844.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 134055413034 its reverse (430314550431), we get a palindrome (564369963465).
The spelling of 134055413034 in words is "one hundred thirty-four billion, fifty-five million, four hundred thirteen thousand, thirty-four".
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