Base | Representation |
---|---|
bin | 111110011011011001… |
… | …1000110100111010001 |
3 | 110211001002211221001110 |
4 | 1330312303012213101 |
5 | 4144030204233043 |
6 | 141330550523533 |
7 | 12454133456304 |
oct | 1746663064721 |
9 | 424032757043 |
10 | 134063352273 |
11 | 519462a3904 |
12 | 21b956665a9 |
13 | c846977ca6 |
14 | 66badd0b3b |
15 | 374994eb33 |
hex | 1f36cc69d1 |
134063352273 has 4 divisors (see below), whose sum is σ = 178751136368. Its totient is φ = 89375568180.
The previous prime is 134063352239. The next prime is 134063352281. The reversal of 134063352273 is 372253360431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 372253360431 = 3 ⋅124084453477.
It is not a de Polignac number, because 134063352273 - 26 = 134063352209 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (134063352373) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22343892043 + ... + 22343892048.
It is an arithmetic number, because the mean of its divisors is an integer number (44687784092).
Almost surely, 2134063352273 is an apocalyptic number.
It is an amenable number.
134063352273 is a deficient number, since it is larger than the sum of its proper divisors (44687784095).
134063352273 is an equidigital number, since it uses as much as digits as its factorization.
134063352273 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 44687784094.
The product of its (nonzero) digits is 272160, while the sum is 39.
The spelling of 134063352273 in words is "one hundred thirty-four billion, sixty-three million, three hundred fifty-two thousand, two hundred seventy-three".
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