1340650411 has 4 divisors (see below), whose sum is σ = 1340805024. Its totient is φ = 1340495800.

The previous prime is 1340650391. The next prime is 1340650433. The reversal of 1340650411 is 1140560431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1140560431 = 22367 ⋅50993.

It is a cyclic number.

It is not a de Polignac number, because 1340650411 - 2¹¹ = 1340648363 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1340650111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63475 + ... + 81916.

It is an arithmetic number, because the mean of its divisors is an integer number (335201256).

Almost surely, 2^1340650411 is an apocalyptic number.

1340650411 is a deficient number, since it is larger than the sum of its proper divisors (154613).

1340650411 is an equidigital number, since it uses as much as digits as its factorization.

1340650411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 154612.

The product of its (nonzero) digits is 1440, while the sum is 25.

The square root of 1340650411 is about 36614.8932949422. The cubic root of 1340650411 is about 1102.6521159978.

The spelling of 1340650411 in words is "one billion, three hundred forty million, six hundred fifty thousand, four hundred eleven".