Base | Representation |
---|---|
bin | 111110011011011111… |
… | …1101111110011101011 |
3 | 110211001100002022122011 |
4 | 1330312333233303223 |
5 | 4144032031313411 |
6 | 141331145540351 |
7 | 12454203602404 |
oct | 1746677576353 |
9 | 424040068564 |
10 | 134066666731 |
11 | 51948158028 |
12 | 21b967a46b7 |
13 | c8475687ca |
14 | 66bb6149ab |
15 | 3749da6c21 |
hex | 1f36fefceb |
134066666731 has 2 divisors, whose sum is σ = 134066666732. Its totient is φ = 134066666730.
The previous prime is 134066666693. The next prime is 134066666837. The reversal of 134066666731 is 137666660431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134066666731 - 29 = 134066666219 is a prime.
It is a super-2 number, since 2×1340666667312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (134066666131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67033333365 + 67033333366.
It is an arithmetic number, because the mean of its divisors is an integer number (67033333366).
Almost surely, 2134066666731 is an apocalyptic number.
134066666731 is a deficient number, since it is larger than the sum of its proper divisors (1).
134066666731 is an equidigital number, since it uses as much as digits as its factorization.
134066666731 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1959552, while the sum is 49.
The spelling of 134066666731 in words is "one hundred thirty-four billion, sixty-six million, six hundred sixty-six thousand, seven hundred thirty-one".
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