Base | Representation |
---|---|
bin | 10011100000101010101… |
… | …000110110011011101011 |
3 | 11202011200211112102210212 |
4 | 103200222220312123223 |
5 | 133431321224220024 |
6 | 2503532501331335 |
7 | 165602625502625 |
oct | 23405250663353 |
9 | 4664624472725 |
10 | 1340745148139 |
11 | 477674757041 |
12 | 197a18a06b4b |
13 | 9957c665c57 |
14 | 48c6cac3c15 |
15 | 24d2104ba0e |
hex | 1382aa366eb |
1340745148139 has 2 divisors, whose sum is σ = 1340745148140. Its totient is φ = 1340745148138.
The previous prime is 1340745148133. The next prime is 1340745148163. The reversal of 1340745148139 is 9318415470431.
It is a weak prime.
It is an emirp because it is prime and its reverse (9318415470431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1340745148139 - 28 = 1340745147883 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (1340745148133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670372574069 + 670372574070.
It is an arithmetic number, because the mean of its divisors is an integer number (670372574070).
Almost surely, 21340745148139 is an apocalyptic number.
1340745148139 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340745148139 is an equidigital number, since it uses as much as digits as its factorization.
1340745148139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1451520, while the sum is 50.
The spelling of 1340745148139 in words is "one trillion, three hundred forty billion, seven hundred forty-five million, one hundred forty-eight thousand, one hundred thirty-nine".
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