Base | Representation |
---|---|
bin | 10011100000101101001… |
… | …111110010011001101001 |
3 | 11202011210212212202100102 |
4 | 103200231033302121221 |
5 | 133431413430102143 |
6 | 2503541103315145 |
7 | 165603666455363 |
oct | 23405517623151 |
9 | 4664725782312 |
10 | 1340788909673 |
11 | 4776974267a4 |
12 | 197a2b5abab5 |
13 | 99588748955 |
14 | 48c74835d33 |
15 | 24d24ce30b8 |
hex | 1382d3f2669 |
1340788909673 has 2 divisors, whose sum is σ = 1340788909674. Its totient is φ = 1340788909672.
The previous prime is 1340788909651. The next prime is 1340788909693. The reversal of 1340788909673 is 3769098870431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 961435158784 + 379353750889 = 980528^2 + 615917^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1340788909673 is a prime.
It is a super-2 number, since 2×13407889096732 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1340788909613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670394454836 + 670394454837.
It is an arithmetic number, because the mean of its divisors is an integer number (670394454837).
Almost surely, 21340788909673 is an apocalyptic number.
It is an amenable number.
1340788909673 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340788909673 is an equidigital number, since it uses as much as digits as its factorization.
1340788909673 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54867456, while the sum is 65.
The spelling of 1340788909673 in words is "one trillion, three hundred forty billion, seven hundred eighty-eight million, nine hundred nine thousand, six hundred seventy-three".
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