Base | Representation |
---|---|
bin | 111110011011111001… |
… | …0111000111100001001 |
3 | 110211002021022110020110 |
4 | 1330313302320330021 |
5 | 4144043444322411 |
6 | 141332345144533 |
7 | 12454425551214 |
oct | 1746762707411 |
9 | 424067273213 |
10 | 134080073481 |
11 | 51954784792 |
12 | 21b9b18b149 |
13 | c84a280bb3 |
14 | 66bd30477b |
15 | 374b1542a6 |
hex | 1f37cb8f09 |
134080073481 has 8 divisors (see below), whose sum is σ = 178790056704. Its totient is φ = 89378402960.
The previous prime is 134080073459. The next prime is 134080073497. The reversal of 134080073481 is 184370080431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 134080073481 - 29 = 134080072969 is a prime.
It is a super-2 number, since 2×1340800734812 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (134080073381) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2040441 + ... + 2105126.
It is an arithmetic number, because the mean of its divisors is an integer number (22348757088).
Almost surely, 2134080073481 is an apocalyptic number.
It is an amenable number.
134080073481 is a deficient number, since it is larger than the sum of its proper divisors (44709983223).
134080073481 is a wasteful number, since it uses less digits than its factorization.
134080073481 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4156351.
The product of its (nonzero) digits is 64512, while the sum is 39.
The spelling of 134080073481 in words is "one hundred thirty-four billion, eighty million, seventy-three thousand, four hundred eighty-one".
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