Base | Representation |
---|---|
bin | 11110011111001100111111… |
… | …101100000100011001001011 |
3 | 122120202110111200001101012011 |
4 | 132133030333230010121023 |
5 | 120033324404021441023 |
6 | 1153102033131000351 |
7 | 40146240316210663 |
oct | 3637147754043113 |
9 | 576673450041164 |
10 | 134085652530763 |
11 | 397a645127a9aa |
12 | 130568458990b7 |
13 | 59a82b85a318b |
14 | 2517accc771a3 |
15 | 1077d1edc150d |
hex | 79f33fb0464b |
134085652530763 has 16 divisors (see below), whose sum is σ = 145452568653504. Its totient is φ = 123106060016640.
The previous prime is 134085652530757. The next prime is 134085652530883. The reversal of 134085652530763 is 367035256580431.
It is a cyclic number.
It is not a de Polignac number, because 134085652530763 - 29 = 134085652530251 is a prime.
It is a super-2 number, since 2×1340856525307632 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 134085652530698 and 134085652530707.
It is not an unprimeable number, because it can be changed into a prime (134085652530163) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5037495 + ... + 17133232.
It is an arithmetic number, because the mean of its divisors is an integer number (9090785540844).
Almost surely, 2134085652530763 is an apocalyptic number.
134085652530763 is a deficient number, since it is larger than the sum of its proper divisors (11366916122741).
134085652530763 is a wasteful number, since it uses less digits than its factorization.
134085652530763 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22179462.
The product of its (nonzero) digits is 54432000, while the sum is 58.
The spelling of 134085652530763 in words is "one hundred thirty-four trillion, eighty-five billion, six hundred fifty-two million, five hundred thirty thousand, seven hundred sixty-three".
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