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134086408740433 = 2131586910721047
BaseRepresentation
bin11110011111001101101100…
…110000110001111001010001
3122120202112110100222210211201
4132133031230300301321101
5120033332431114143213
61153102240143111201
740146265130661622
oct3637155460617121
9576675410883751
10134086408740433
11397a67aa121476
1213056a16ba2501
1359a83a9163216
142517b61483a49
151077d664986dd
hex79f36cc31e51

134086408740433 has 8 divisors (see below), whose sum is σ = 134172200352320. Its totient is φ = 134000638586640.

The previous prime is 134086408740331. The next prime is 134086408740551. The reversal of 134086408740433 is 334047804680431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134086408740433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134086405740433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7146316 + ... + 17867362.

It is an arithmetic number, because the mean of its divisors is an integer number (16771525044040).

Almost surely, 2134086408740433 is an apocalyptic number.

It is an amenable number.

134086408740433 is a deficient number, since it is larger than the sum of its proper divisors (85791611887).

134086408740433 is a wasteful number, since it uses less digits than its factorization.

134086408740433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10729047.

The product of its (nonzero) digits is 18579456, while the sum is 55.

The spelling of 134086408740433 in words is "one hundred thirty-four trillion, eighty-six billion, four hundred eight million, seven hundred forty thousand, four hundred thirty-three".

Divisors: 1 2131 5869 10721047 12506839 22846551157 62921824843 134086408740433