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134097121 = 276748463
BaseRepresentation
bin1111111111000…
…10100011100001
3100100022211200001
413333202203201
5233312101441
621150100001
73215543464
oct777424341
9310284601
10134097121
1169770174
1238aaa601
1321a21612
1413b492db
15bb8c731
hex7fe28e1

134097121 has 4 divisors (see below), whose sum is σ = 134148352. Its totient is φ = 134045892.

The previous prime is 134097113. The next prime is 134097127. The reversal of 134097121 is 121790431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 134097121 - 23 = 134097113 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 134097121.

It is not an unprimeable number, because it can be changed into a prime (134097127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21465 + ... + 26998.

It is an arithmetic number, because the mean of its divisors is an integer number (33537088).

Almost surely, 2134097121 is an apocalyptic number.

It is an amenable number.

134097121 is a deficient number, since it is larger than the sum of its proper divisors (51231).

134097121 is an equidigital number, since it uses as much as digits as its factorization.

134097121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51230.

The product of its (nonzero) digits is 1512, while the sum is 28.

The square root of 134097121 is about 11580.0311312189. The cubic root of 134097121 is about 511.8465943101.

The spelling of 134097121 in words is "one hundred thirty-four million, ninety-seven thousand, one hundred twenty-one".

Divisors: 1 2767 48463 134097121