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134101043103 = 31920681113759
BaseRepresentation
bin111110011100100001…
…0111000011110011111
3110211010201202211011010
41330321002320132133
54144114331334403
6141334414430303
712455102026146
oct1747102703637
9424121684133
10134101043103
11519655a7555
1221ba6202393
13c851713761
1466c200275d
15374cde7603
hex1f390b879f

134101043103 has 16 divisors (see below), whose sum is σ = 188222745600. Its totient is φ = 84690555840.

The previous prime is 134101043057. The next prime is 134101043137. The reversal of 134101043103 is 301340101431.

It is not a de Polignac number, because 134101043103 - 213 = 134101034911 is a prime.

It is a super-2 number, since 2×1341010431032 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 134101043103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134101043803) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1121938 + ... + 1235696.

It is an arithmetic number, because the mean of its divisors is an integer number (11763921600).

Almost surely, 2134101043103 is an apocalyptic number.

134101043103 is a deficient number, since it is larger than the sum of its proper divisors (54121702497).

134101043103 is a wasteful number, since it uses less digits than its factorization.

134101043103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 134462.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 134101043103 its reverse (301340101431), we get a palindrome (435441144534).

The spelling of 134101043103 in words is "one hundred thirty-four billion, one hundred one million, forty-three thousand, one hundred three".

Divisors: 1 3 19 57 20681 62043 113759 341277 392939 1178817 2161421 6484263 2352649879 7057949637 44700347701 134101043103