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134101056233 is a prime number
BaseRepresentation
bin111110011100100001…
…0111011101011101001
3110211010201210111011102
41330321002323223221
54144114332244413
6141334415011145
712455102112344
oct1747102735351
9424121714142
10134101056233
1151965606401
1221ba6209ab5
13c851719721
1466c200745b
15374cdeb458
hex1f390bbae9

134101056233 has 2 divisors, whose sum is σ = 134101056234. Its totient is φ = 134101056232.

The previous prime is 134101056209. The next prime is 134101056247. The reversal of 134101056233 is 332650101431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110560905049 + 23540151184 = 332507^2 + 153428^2 .

It is an emirp because it is prime and its reverse (332650101431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134101056233 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 134101056196 and 134101056205.

It is not a weakly prime, because it can be changed into another prime (134101056203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67050528116 + 67050528117.

It is an arithmetic number, because the mean of its divisors is an integer number (67050528117).

Almost surely, 2134101056233 is an apocalyptic number.

It is an amenable number.

134101056233 is a deficient number, since it is larger than the sum of its proper divisors (1).

134101056233 is an equidigital number, since it uses as much as digits as its factorization.

134101056233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6480, while the sum is 29.

Adding to 134101056233 its reverse (332650101431), we get a palindrome (466751157664).

The spelling of 134101056233 in words is "one hundred thirty-four billion, one hundred one million, fifty-six thousand, two hundred thirty-three".