Base | Representation |
---|---|
bin | 111110011100100101… |
… | …0010101111001101001 |
3 | 110211010212110011122011 |
4 | 1330321022111321221 |
5 | 4144120331424013 |
6 | 141334524355521 |
7 | 12455124452332 |
oct | 1747112257151 |
9 | 424125404564 |
10 | 134102998633 |
11 | 5196671279a |
12 | 21ba69a5ba1 |
13 | c851c49886 |
14 | 66c2391289 |
15 | 374d181c3d |
hex | 1f39295e69 |
134102998633 has 2 divisors, whose sum is σ = 134102998634. Its totient is φ = 134102998632.
The previous prime is 134102998619. The next prime is 134102998637. The reversal of 134102998633 is 336899201431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 108206786704 + 25896211929 = 328948^2 + 160923^2 .
It is a cyclic number.
It is not a de Polignac number, because 134102998633 - 221 = 134100901481 is a prime.
It is a super-2 number, since 2×1341029986332 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (134102998637) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67051499316 + 67051499317.
It is an arithmetic number, because the mean of its divisors is an integer number (67051499317).
Almost surely, 2134102998633 is an apocalyptic number.
It is an amenable number.
134102998633 is a deficient number, since it is larger than the sum of its proper divisors (1).
134102998633 is an equidigital number, since it uses as much as digits as its factorization.
134102998633 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 839808, while the sum is 49.
The spelling of 134102998633 in words is "one hundred thirty-four billion, one hundred two million, nine hundred ninety-eight thousand, six hundred thirty-three".
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