Base | Representation |
---|---|
bin | 10011100000111100011… |
… | …101010110011000011001 |
3 | 11202012110200002221102211 |
4 | 103200330131112120121 |
5 | 133432424243420121 |
6 | 2504022301355121 |
7 | 165613215653131 |
oct | 23407435263031 |
9 | 4665420087384 |
10 | 1341044123161 |
11 | 4778084a0436 |
12 | 197aa0b68aa1 |
13 | 995c9595352 |
14 | 48c9a6abac1 |
15 | 24d3c406ce1 |
hex | 1383c756619 |
1341044123161 has 2 divisors, whose sum is σ = 1341044123162. Its totient is φ = 1341044123160.
The previous prime is 1341044123087. The next prime is 1341044123197. The reversal of 1341044123161 is 1613214401431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 883682721936 + 457361401225 = 940044^2 + 676285^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1341044123161 is a prime.
It is not a weakly prime, because it can be changed into another prime (1341045123161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670522061580 + 670522061581.
It is an arithmetic number, because the mean of its divisors is an integer number (670522061581).
Almost surely, 21341044123161 is an apocalyptic number.
It is an amenable number.
1341044123161 is a deficient number, since it is larger than the sum of its proper divisors (1).
1341044123161 is an equidigital number, since it uses as much as digits as its factorization.
1341044123161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 31.
Adding to 1341044123161 its reverse (1613214401431), we get a palindrome (2954258524592).
The spelling of 1341044123161 in words is "one trillion, three hundred forty-one billion, forty-four million, one hundred twenty-three thousand, one hundred sixty-one".
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