Base | Representation |
---|---|
bin | 1100001100100110001000… |
… | …0101010000000111100001 |
3 | 1202111000221010121012021102 |
4 | 3003021202011100013201 |
5 | 3224204233030121032 |
6 | 44304414121004145 |
7 | 2552610343314035 |
oct | 303114205200741 |
9 | 52430833535242 |
10 | 13410533442017 |
11 | 4300414574a78 |
12 | 1607074623655 |
13 | 7637b967788a |
14 | 34510512a1c5 |
15 | 183c8abb0362 |
hex | c32621501e1 |
13410533442017 has 2 divisors, whose sum is σ = 13410533442018. Its totient is φ = 13410533442016.
The previous prime is 13410533441989. The next prime is 13410533442023. The reversal of 13410533442017 is 71024433501431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13406904463936 + 3628978081 = 3661544^2 + 60241^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13410533442017 is a prime.
It is not a weakly prime, because it can be changed into another prime (13410533445017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705266721008 + 6705266721009.
It is an arithmetic number, because the mean of its divisors is an integer number (6705266721009).
Almost surely, 213410533442017 is an apocalyptic number.
It is an amenable number.
13410533442017 is a deficient number, since it is larger than the sum of its proper divisors (1).
13410533442017 is an equidigital number, since it uses as much as digits as its factorization.
13410533442017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120960, while the sum is 38.
Adding to 13410533442017 its reverse (71024433501431), we get a palindrome (84434966943448).
The spelling of 13410533442017 in words is "thirteen trillion, four hundred ten billion, five hundred thirty-three million, four hundred forty-two thousand, seventeen".
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