Base | Representation |
---|---|
bin | 1100001100100110001000… |
… | …1100110001101010100011 |
3 | 1202111000221021022101220221 |
4 | 3003021202030301222203 |
5 | 3224204234031230220 |
6 | 44304414231143511 |
7 | 2552610366140365 |
oct | 303114214615243 |
9 | 52430837271827 |
10 | 13410535414435 |
11 | 43004156a1975 |
12 | 1607075214b97 |
13 | 7637b9bb85a3 |
14 | 3451054c0d35 |
15 | 183c8ae4e9aa |
hex | c3262331aa3 |
13410535414435 has 16 divisors (see below), whose sum is σ = 16319547887040. Its totient is φ = 10577162673280.
The previous prime is 13410535414349. The next prime is 13410535414453. The reversal of 13410535414435 is 53441453501431.
It is not a de Polignac number, because 13410535414435 - 221 = 13410533317283 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13410535414391 and 13410535414400.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26598549 + ... + 27098041.
It is an arithmetic number, because the mean of its divisors is an integer number (1019971742940).
Almost surely, 213410535414435 is an apocalyptic number.
13410535414435 is a deficient number, since it is larger than the sum of its proper divisors (2909012472605).
13410535414435 is an equidigital number, since it uses as much as digits as its factorization.
13410535414435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 575198.
The product of its (nonzero) digits is 864000, while the sum is 43.
Adding to 13410535414435 its reverse (53441453501431), we get a palindrome (66851988915866).
The spelling of 13410535414435 in words is "thirteen trillion, four hundred ten billion, five hundred thirty-five million, four hundred fourteen thousand, four hundred thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •