13411005311401 has 2 divisors, whose sum is σ = 13411005311402. Its totient is φ = 13411005311400.

The previous prime is 13411005311369. The next prime is 13411005311449. The reversal of 13411005311401 is 10411350011431.

13411005311401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9067469978176 + 4343535333225 = 3011224^2 + 2084115^2 .

It is a cyclic number.

It is not a de Polignac number, because 13411005311401 - 2⁵ = 13411005311369 is a prime.

It is not a weakly prime, because it can be changed into another prime (13411095311401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705502655700 + 6705502655701.

It is an arithmetic number, because the mean of its divisors is an integer number (6705502655701).

Almost surely, 2^{13411005311401} is an apocalyptic number.

It is an amenable number.

13411005311401 is a deficient number, since it is larger than the sum of its proper divisors (1).

13411005311401 is an equidigital number, since it uses as much as digits as its factorization.

13411005311401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 25.

Adding to 13411005311401 its reverse (10411350011431), we get a palindrome (23822355322832).

The spelling of 13411005311401 in words is "thirteen trillion, four hundred eleven billion, five million, three hundred eleven thousand, four hundred one".